Question

The four consecutive natural numbers whose sum is 98 are

Answer 1

Step-by-step explanation:

Let the four consecutive natural numbers = a, a+1, a+2, a+3

their sum = 98

=> a + a+1 + a+2 + a+3 = 98

=> 4a + 6 = 98

=> 4a = 98-6 = 92

=> a = 92/4 = 23

the four consecutive natural numbers = a, a+1, a+2, a+3 = 23, 25, 35 and 26