The four walls and bottom surface of a
swimming pool are to be painted. Find the total
cost of painting at the rate of
450 per m2,
if the dimensions of the pool are length = 10m,
breadth = 4 m and depth = 2 m
Answers
Given -
- Dimensions of pool = 10m × 4m × 2m
- Rate of painting = ₹450 per m²
To find -
- Cost of painting
Formula used -
- LSA of cuboid
- Area of rectangle
Solution -
Here, the length, Breadth and height of a pool is give, and we have to find the cost of painting the four walls and surface of the swiming pool, for that first we will find the area of the four walls, and then the area of the bottom of the pool, then we will add both the areas, and then we will find the total cost of painting.
Now -
Lateral surface area of cuboid = 2h(l + b)
Where -
h = Height
l = Length
b = Breadth
On substituting the values -
Area = 2h(l + b)
Area = 2 × 2m (10m + 4m)
Area = 4m × 14m
Area = 56m²
Now -
As, the bottom of the swimming pool, is in the shape of rectangle, therefore, we will use the formula of area of rectangle.
Area of rectangle = L × B
On substituting the values -
Area = L × B
Area = 10m × 4m
Area = 40m²
Now -
Total area = Area of four walls + Area of bottom
Total area = 56m² + 40m²
Total area = 96m²
At the end -
Total cost = Area of pool × given rate
Total cost = 96m × ₹450
Total cost = ₹43200
Total cost is ₹43200
______________________________________________
Answer:-
★★ Dimensions of the pool
- Length = 10m
- Breadth = 4m
- Depth = 2m
★★ Rate of painting = ₹450/m²
We need to find the cost of thr painting the four walls and the bottom surface of the swimming pool
Area of the swimming pool to be painted = Area of four walls + area of the floor
= 2×height(length+breadth) + length × breadth
= 2 × 2(10+4) + 10 × 4
= 2× 2 × 14 + 40
= 28 × 2 + 40
= 56m² + 40m²
= 96m²
Given, Rate of painting = ₹450/m²
∴ Cost of painting the swimming pool = ₹450 × 96 m²
= ₹43200
Answer : The cost of painting the swimming pool is ₹ 43200.00