Question

the fourth and seventh terms of an AP are 3 and 36.find the a.p and its fifteenth term​

Answer 1

Step-by-step explanation:

a4 = 3

a7 = 36

so, a+ 3d = 3

a+ 6d = 36

-3d = -33

d = 11

so, put d in eq. 1

a + 3d = 3

a + 3* 11 = 3

a + 33 = 3

so, a= 3 - 33

a = -30

A.P = -30,-19,-8,.....

Now , a5 = a+ 4d

= -30 + 4*11

= -30 + 44

a5 = 14

Answer 2

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