Question

the fourth term of the agp 6,8,8,

Answer 1

a= 6 r=8/6=4/3 t4= ar3=

Answer 2

Answer:

0 or 64/9

Step-by-step explanation:

Tn= (a+(n-1)d)$r^{n-1}$

T2=(6+d)r=8

T3=(6+2d)$r^{2}$=8

As T2=T3

6+d=(6+2d)r

Thus d=6(1-r)/(2r-1)

⇒T2=(6+6(1-r)/(2r-1))r=8

on solving⇒3r²-8r+4=0

r=2 or 2/3

if r=2   d=-2 (sub in eq for t2) T4=0

if r=64/9    d=6     T4=64/9