Math, asked by mshande1979, 11 months ago

The fourth vertex D of a parallelogram ABCD whose three vertices are A(-2,5), B(6,9) and C(8,5) is​

Answers

Answered by rani49035
17

Answer:

forth vertex can be found by the given formula..

i.e. x' = sum of. x coordinates of A and B - x of C

y' = sum of. y coordinates of A and B - y of C

here x' and y' are the coordinates of unknown vertex

put the values and get your answer..

x =. -2+8- 6 = 0

y = 5 + 5 -9 = 1

so the coordinates of forth vertex are (0,1)

hope this will help you

Similar questions