The fourth vertex D of a parallelogram ABCD whose three vertices are A(-2,5), B(6,9) and C(8,5) is
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forth vertex can be found by the given formula..
i.e. x' = sum of. x coordinates of A and B - x of C
y' = sum of. y coordinates of A and B - y of C
here x' and y' are the coordinates of unknown vertex
put the values and get your answer..
x =. -2+8- 6 = 0
y = 5 + 5 -9 = 1
so the coordinates of forth vertex are (0,1)
hope this will help you
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