Math, asked by TheHoneyBabe, 1 month ago

The fourth vertex D of a parallelogram ABCD whose three vertices are A(-2,3), B(6, 7), C(10.3) is (a) (0, 1) (b) (2, - 1) (c) (-1,0) (d) (1,0) БА B. Do Do
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Answers

Answered by KrithikaQueen
2

Step-by-step explanation:

The fourth vertex D of a parallelogram ABCD whose three vertices are A(-2,3), B(6,7) and C(8,3) is. Let the fourth vertex of parallelogram , D ≡(x4,y4)and L,M be the middle points of AC and BD , respectively. Hence , the fourth vertex of parallelogram is D ≡(x4,y4)≡(0,1).

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Answered by βαbγGυrl
0

Answer:

The fourth vertex D of a parallelogram ABCD whose three vertices are A(–2, 3), B(6, 7) and C(8, 3) is (0, –1).

Since, ABCD is a parallelogram, therefore diagonals AC and BD will bisect each other.

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