The fourth vertex D of a parallelogram ABCD whose three vertices are A (–2, 3), B (6, 7) and C (8, 3) is
(0, 1)
(-1, 0)
(0, -1)
(1, 0)
Answers
Answered by
0
Answer:
(0,1)
Let the fourth vertex D =(x,y)
We know that the diagonals of a parallelogram bisect each other. So,the
midpoint of AC is same as the mid point of BD.
Mid point of two points (x
1
,y
1
) and (x
2
,y
2
) is calculated by the formula (
2
x
1
+x
2
,
2
y
1
+y
2
)
So, midpoint of AC= Mid point of BD
=>(
2
−2+8
,
2
3+3
)=(
2
6+x
,
2
7+y
)
=>(
2
6
,
2
6
)=(
2
6+x
,
2
7+y
)
=>6+x=6;7+y=6
=>x=0;y=−1
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