Math, asked by raghasreesundar, 1 month ago

The fourth vertex D of a parallelogram ABCD whose three vertices are A (–2, 3), B (6, 7) and C (8, 3) is
(0, 1)
(-1, 0)
(0, -1)
(1, 0)​

Answers

Answered by rachelgangmei2003
0

Answer:

(0,1)

Let the fourth vertex D =(x,y)

We know that the diagonals of a parallelogram bisect each other. So,the

midpoint of AC is same as the mid point of BD.

Mid point of two points (x

1

,y

1

) and (x

2

,y

2

) is calculated by the formula (

2

x

1

+x

2

,

2

y

1

+y

2

)

So, midpoint of AC= Mid point of BD

=>(

2

−2+8

,

2

3+3

)=(

2

6+x

,

2

7+y

)

=>(

2

6

,

2

6

)=(

2

6+x

,

2

7+y

)

=>6+x=6;7+y=6

=>x=0;y=−1

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