Question

The fraction of ice that melts by mixing equal masses of ice at -10"C and water at 60-C

Answer 1

Answer:

100

Explanation:

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Answer 2

Answer:

The fraction of ice that melts by mixing equal masses of ice at -10°C and water at 60°C is $\frac{5}{16}$.

Explanation:

Let in denote the initial masses of water and ice, respectively, and x denote the mass of ice melting.

Heat absorbed = ms∣ΔTice∣ + xLf

Δθ absorbed = m(1)(10) + x(80)

Heat released = msΔT water

ΔH released = m(1)(60)

ΔH released = 60 m

As Δθ observed = ΔH released

⇒ 10 m + 80 x = 60 m

⇒ 80 x = 50 m ⇒ x = $\frac{5}{8}$m

Thus, fraction of ice melted = $\frac{x}{2m}$ = $\frac{5}{8}$m = $\frac{5}{16}$