Chemistry, asked by Smitamadhu, 1 year ago

The freezing point of 1 molal Molal NaCl Solution assuming NaCl to be 100% Dissociated in water is _____.(Kf=1.86)

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Answered by sharpyy
51
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Answered by IlaMends
20

Answer:

The freezing point of 1 molal NaCl Solution assuming NaCl to be 100% Dissociated in water is -3.72°C.

Explanation:

The depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T-T_f

where,

\Delta T_f= change in boiling point  = 0.81 K

T_f=Boiling point of the solution

T = freezing point of the pure solvent

i = van't Hoff factor

K_f = freezing point constant  = 1.86 K/kg mol

m = molality

Given: m = 1 m, K_f=1.86 °C/kg mol

Freezing point of water = T = 0°C

NaCl\rightarrow Na^++Cl^-

100% dissociation means sodium chlorides dissociates completely in its aqueous solution.The two ions are formed in the solution :Na^+,Cl^-

i = 2

\Delta T_f=2\times 1.86 ^oC/kg mol\times 1m=3.72^oC

\Delta T_f=3.72^oC=0^oC-T_f

T_f=-3.72^oC

The freezing point of 1 molal NaCl Solution assuming NaCl to be 100% Dissociated in water is -3.72°C.

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