Question

The freezing point of one molal nacl solution assuming nacl to be 100 % dissociation

Answer 1

Depression in freezing point is given by

∆Tf=i*Kf*m

Here, i=2

m=1

Therefore,

∆Tf=2Kf

Since Kf for water is 1.86

∆Tf=3.72

∆Tf=T°f-Tf

Tf=T°f-∆Tf

= 273.15-3.72

= 269.43 K

Answer 2

Answer:

Explanation:

Refer the below attachment.