Question

The freezing point on a thermometer is marked as 20 A and the boiling point as 120A find the value of temperature 80 C on this thermometer​

Answer 1

Answer:

100A.

Explanation:

120A -> 100 *C

20A -> 0 *C

So, let T(C) = aT(A) + b

Putting T(C) = 0, T(A) = 20:

0 = 20a + b    ...1

And T(C) = 100, T(A) = 120:

100 = 120a + b    ...2

2 - 1:

100a = 100

=> a = 1    ...3

3 in 1:

0 = 20 * (1) + b

=> b = -20

So, T(C) = T(A) - 20

Putting T(C) = 80:

80 = T(A) - 20

T(A) = 100.

So, temperature on the given thermometer = 100A.