Question

The frequency of a light wave in a material is 2 × 10¹⁴ Hz and wavelength is 5000 Å. The refractive index of material will be(a) 1.50(b) 3.00(c) 1.33(d) 1.40

Answer 1

Answer:

B) 3

Explanation:

Frequency of a light wave in a material  = 2 × 10¹⁴ Hz  (Given)

Wavelength = 5000Å (Given)

Refractive index of  material -

u = velocity of light in vaccum (c)/ velocity of light in medium (v)

Thus,

By using v = nλ , n = 2 x 10¹⁴ Hz

λ = 5000Å = 5000 x 10⁻¹⁰ m

v = 2 x 10¹⁴ x 5000 x 10⁻¹⁰ = 10⁸ m/s

Refractive index of the material,

µ = c / v

= 3 x 10⁸ / 10⁸

= 3

Thus the refractive index of material will be = 3

Answer 2

Answer:

B) 3

Explanation:

Frequency of a light wave in a material  = 2 × 10¹⁴ Hz  (Given)

Wavelength = 5000Å (Given)

Refractive index of  material -

u = velocity of light in vaccum (c)/ velocity of light in medium (v)

Thus,

By using v = nλ , n = 2 x 10¹⁴ Hz

λ = 5000Å = 5000 x 10⁻¹⁰ m

v = 2 x 10¹⁴ x 5000 x 10⁻¹⁰ = 10⁸ m/s

Refractive index of the material,

µ = c / v

= 3 x 10⁸ / 10⁸

= 3

Thus the refractive index of material will be = 3

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Explanation: