The frequency of revolution of electron in nth orbit is fn .If the electron mskes a transition from nth orbit to (n-1)th orbit ,then the relation between the frequency of emitted photon and fn will be
Answers
Answered by
0
Email Login DONATE
logo Ask Questions, Get Answers
Questions >> JEEMAIN and NEET >> Chemistry >> Atomic Structure
Next similar questionQ)
Determine the frequency of revolution of the electron in 2nd Bohr's orbit in hydrogen atom
(a)9.3×1015Hz(c)7.32×1016Hz(b)8.28×1016Hz(d)8.13×1016Hz
Homework help Revision notes Donate
A)
Frequency = 1Time period
Time period = Total distance coveredVelocity=2πrv
Frequency = v2πr
The velocity (v2) and radius (r2) of the 2nd Bohr's orbit :
rn=(0.53×10−10n2/z)m
r2=(0.53×10−10(22)m=2.12×10−100m
vn=2.165×106(z/n)m/s
v2=2.165×106(1/2)=1.082×106m/s
Frequency=v22πr2=1.082×1062(π)(2.12×10−10)
v=8.13×1016Hz
Hence (d) is the correct option.
Similar questions
Physics,
1 year ago
Social Sciences,
1 year ago