Physics, asked by aanchit608, 1 year ago

The frequency of revolution of electron in nth orbit is fn .If the electron mskes a transition from nth orbit to (n-1)th orbit ,then the relation between the frequency of emitted photon and fn will be

Answers

Answered by pardeep2440
0

Email Login DONATE

logo Ask Questions, Get Answers

Questions >> JEEMAIN and NEET >> Chemistry >> Atomic Structure

Next similar questionQ)

Determine the frequency of revolution of the electron in 2nd Bohr's orbit in hydrogen atom

(a)9.3×1015Hz(c)7.32×1016Hz(b)8.28×1016Hz(d)8.13×1016Hz

Homework help Revision notes Donate

A)

Frequency = 1Time period

Time period = Total distance coveredVelocity=2πrv

Frequency = v2πr

The velocity (v2) and radius (r2) of the 2nd Bohr's orbit :

rn=(0.53×10−10n2/z)m

r2=(0.53×10−10(22)m=2.12×10−100m

vn=2.165×106(z/n)m/s

v2=2.165×106(1/2)=1.082×106m/s

Frequency=v22πr2=1.082×1062(π)(2.12×10−10)

v=8.13×1016Hz

Hence (d) is the correct option.

Similar questions