Question

The frequency of the fundamental note
in a wire stretched under tension Tis v.
if the tension is increased to 25T, then
the frequency of the fundamental note
will be​

Answer 1

Answer:

Frequency of a fundamental note, v =

$\frac{n}{2l} \sqrt{ \frac{t}{u} }$

Assuming, harmonics, length and mass constant, then f directly varies with

$sqrt{t}$

So,

v1/v2 =

$\sqrt{ \frac{t1}{t2} }$

Here, t2 = 25t1

So, v1/v2 = 1/5 i.e. v2 = 5v1