The front wheels of a wagon are 2 feet in circumference and the back wheels are 3 feet in circumference. When the front wheels have made 10 more revolutions than the back wheels, how many feet has the wagon travelled?
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distance covered by small wheel in (x + 10 ) revolution = 2 ( x + 10)
distance covered by big wheel in x revolution = 3x
both wheel should cover equal distance so
2(x+10)= 3x
2x+ 20 = 3x
x = 20
so distance covered = 3*20 = 60 feet
I hope my answer is correct
distance covered by big wheel in x revolution = 3x
both wheel should cover equal distance so
2(x+10)= 3x
2x+ 20 = 3x
x = 20
so distance covered = 3*20 = 60 feet
I hope my answer is correct
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1
Answer:it's pull the answee
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