The function 4 (n) = 2x²-yxt 10 in o interval [2,3] satisfied the value of 아 CE (2,5) by larunge's mean Value Therom. (5/2)
Answers
Answered by
0
Answer:
Applying Lagrange's mean value theorem, we get
a−1
f(a)−f(1)
=f
′
(2)
a−1
2a
2
+3a+5−10
=4x+3∣
x=2
a−1
2a
2
+3a−5
=11
2a
2
+3a−5=11a−11
2a
2
−8a+6=0
a
2
−4a+3=0
(a−3)(a−1)=0
a=3 and a=1
However
aϵ[1,a]
Hence
a=3.
Similar questions