Question

The function f is defined on the real numbers by f(x) = 2 + x - x2: What is the value of f (2)?​

Answer 1

hope this will help u dear

Answer 2

SOLUTION

GIVEN

The function f is defined on the real numbers by

$\sf{ f(x) = 2 + x - {x}^{2} \: }$

TO DETERMINE

The value of f (2)

EVALUATION

Here

$\sf{ f(x) = 2 + x - {x}^{2} \: }$

Putting x = 2 in both sides we get

$\sf{ f(2) = 2 + 2 - {(2)}^{2} \: }$

$\implies \sf{ f(2) = 4 - 4}$

$\implies \sf{ f(2) =0 \: }$

FINAL ANSWER

$\boxed{ \sf{ \: \: f(2) = 0 \: } \: \: }$

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ADDITIONAL INFORMATION

The value of x for which f(x) = 0 is called the zero of the polynomial

So for the above mentioned polynomial 2 is the zero of the polynomial

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LEARN MORE FROM BRAINLY

Let A={(x,y):x,y€z,x²+y²≤16},

then the number of reflexive relations on set A

is...a)2^49 b)2^2401 c)2^2352 d)2^1176

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