Question

The function g(x) = x2 – 10x + 24 is graphed on a coordinate plane. Where will the function cross the x-axis? (–6, 0) and (–4, 0) (–2, 0) and (–12, 0) (4, 0) and (6, 0) (12, 0) and (2, 0)

Answer 1

Given function is $g(x) = x^{2}-10x+24$

To find where the function crosses the x-axis for that we have to find the x-intercepts and for that we have to find the factors of the given equation.

$g(x) = x^{2}-10x+24$

$g(x) = (x-6)(x-4)$

To find the x-intercept put g(x) = 0

$(x-6)(x-4) = 0$

$(x-6)= 0$  and $(x-4) = 0$

So, x= 6 and x = 4

So the given function crosses X-axis ate (6,0) and (4,0)

Answer 2

Answer:

it's C amigos | x=4, x=6

Step-by-step explanation:

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