Math, asked by yogeshkumar9029, 1 year ago

The function given by y = ||x| – 1| is differentiable for all real numbers except the points
(a) {0, 1,–1}
(b) ±1
(c) 1
(d) –1

Answers

Answered by brunoconti
3

Answer:

Step-by-step explanation:

f(x) = | |x| - 1 | is differentiable everywhere but at - 1 , 0 and 1.

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