Question

the function is given f(x)=(9x/5)+32. 1) f(0) 2)f(-10) 3) find x such that f(x) = 22

Answer 1

1)  f(0)= (9(0)/5)+32
          = (0/5)+32)
          = 0+32
         =32

2) f(-10)= (9(-10)/5)+32
             = (-90/5)+32
             = -18+32
             = 14

3) f(x)=22
   => (9x/5)+32= 22
   => solve this part yourself.

(answer= x=-50/9)