Question

The function method chechbirthday returnd an integer 1 if it is her birthday else 0

Answer 1

Answer:

Step-by-step explanation:

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2

This question already has an answer here:

How to check if a float value is a whole number 13 answers

How to make python print 1 as opposed to 1.0 3 answers

In Python is there a way to turn 1.0 into a integer 1 while the same function ignores 1.5 and leaves it as a float?

Right now, int() will turn 1.0 into 1 but it will also round 1.5 down to 1, which is not what I want.

python floating-point integer

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edited Apr 24 at 2:42

U10-Forward

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asked Apr 4 at 7:46

Raymond Shen

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marked as duplicate by Martijn Pieters♦ python Apr 23 at 10:32

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4

one way could be to check the float using is_integer() if that passes, convert it to int? – DirtyBit Apr 4 at 7:47  

7

Floats are approximations, 1.0 could actually be 1.00000000000001 or 0.999999999999. – Barmar Apr 4 at 7:49

6

Note that because of duck typing, this passage you want to achieve is probably out of place or useless, depending on context. – Federico S Apr 4 at 7:52

13

Please specify your exact requirements in words/rules rather than just with a single example! – Lightness Races in Orbit Apr 4 at 10:35

5

def f(x): if x == 1.0: return 1 else return 1.5 – Bakuriu Apr 4 at 20:26

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10 Answers

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79

Continuing from the comments above:

Using is_integer():

Example from the docs:

>>> (1.5).is_integer()

False

>>> (1.0).is_integer()

True

>>> (1.4142135623730951).is_integer()

False

>>> (-2.0).is_integer()

True

>>> (3.2).is_integer()

False

INPUT:

s = [1.5, 1.0, 2.5, 3.54, 1.0, 4.4, 2.0]

Hence:

print([int(x) if x.is_integer() else x for x in s])

Wrapped in a function:

def func(s):

   return [int(x) if x.is_integer() else x for x in s]

print(func(s))

If you do not want any import:

def func(s):

   return [int(x) if x == int(x) else x for x in s]

print(func(s))

Using map() with lambda function and the iter s:

print(list(map(lambda x: int(x) if x.is_integer() else x, s)))

OR

print(list(map(lambda x: int(x) if int(x) == x else x, s)))

OUTPUT: