The function whose first forward difference is e
x
is (interval of differencing being ”h”)
(a) e
x
.
(b) e
x+h − e
x
.
(c) e
x − e
x−h
.
(d) e
x
(e
h − 1).
Answers
Answered by
0
Answer:
The function whose first forward difference is e
x
is (interval of differencing being ”h”)
(a) e
x
.
(b) e
x+h − e
x
.
(c) e
x − e
x−h
.
(d) e
x
(e
h − 1).
Similar questions