The function y = ax + 2a² is a solution of the differential equations
(a) 2(y’)² + xy’ + y = 0
(b) 2(y’)² − xy’ + y = 0
(c) 2(y’)² + xy’ − y = 0
(d) none of these
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So by the above process the option is 4
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The correct answer is option(d) none of these
we have y=cx-c²
On differentiating w.r.t x we get y'=c
On putting this value in the equation we get ,
y=x(y')-(y')²
⇒(y')²-xy'+y=0
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