The fundamental frequency in an open organ pipe is equal to the third harmonic of a closed organ pipe. if the lenght pf the closed organ pipe is 20cm the lenght of open pipe is
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Given, Here in Question ⇒
Fundamental Frequency for the Open orange pipe is given by ⇒ ν/2l'
Where,
ν (neu) = Frequency &
l' is the length of the open orange pipe.
Also, We know,
Third Harmonic of the orange pipe = 3ν/4l
where,
ν = frequency & l is the length of the Closed orange pipe = 20 cm.
Now, According to the Question,
3ν/4l = ν/2l'
→ 3/(4 × 20) = 1/2l'
→ 3/80 = 1/2l'
→ 2l' = 80/3
∴ l' = 40/3
∴ l' = 13.33 cm.
Thus, the length of the open orange pipe = 13.33 cm.
Hope it helps.
Fundamental Frequency for the Open orange pipe is given by ⇒ ν/2l'
Where,
ν (neu) = Frequency &
l' is the length of the open orange pipe.
Also, We know,
Third Harmonic of the orange pipe = 3ν/4l
where,
ν = frequency & l is the length of the Closed orange pipe = 20 cm.
Now, According to the Question,
3ν/4l = ν/2l'
→ 3/(4 × 20) = 1/2l'
→ 3/80 = 1/2l'
→ 2l' = 80/3
∴ l' = 40/3
∴ l' = 13.33 cm.
Thus, the length of the open orange pipe = 13.33 cm.
Hope it helps.
Answered by
0
Answer:
Fundamental Frequency for the Open orange pipe is given by ⇒ ν/2l'
Where,
ν (neu) = Frequency &
l' is the length of the open orange pipe.
Also, We know,
Third Harmonic of the orange pipe = 3ν/4l
where,
ν = frequency & l is the length of the Closed orange pipe = 20 cm.
Now, According to the Question,
3ν/4l = ν/2l'
→ 3/(4 × 20) = 1/2l'
→ 3/80 = 1/2l'
→ 2l' = 80/3
∴ l' = 40/3
∴ l' = 13.33 cm.
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