Question

the fundamental frequency of oscillation of one end closed pipe is 400 Hertz. what will be the fundamental frequency of oscillation of 2 and open pipe of same length?

Answer 1

Frequency (v1) =velocity(V) /lambda
400 =V/4l
Therefore l =V/1600--------(1)
Since closed and open organ pipe has the same length
For open organ pipe
v2=V/2l--------(2)
From (1) and (2)
We get,
v2=800hz
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