the garph of linear equation 2x+3y=6 cuts the y-axis at the point
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•2x+3y=6
Since , the line intersects at y−axis.
Put x=0 in the given equation
⇒y=2
Hence, the line intersects y−axis at (0,2)
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we know that the point on the y-axis will have the x-coordinate as 0.
this means that the point at which the graph of linear equation 2x + 3y = 6 cuts the y-axis is '(0, y)'.
Hence, the point at which the graph of linear equation 2x + 3y = 6 cuts the y-axis is y(0, 2).
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