Question

The GCD of two numbers is 16 and the first four quotients obtained in the division are equal to 2. Then the no. are

Answer 1

Given:

GCD = 16

To find:

x and y = ?

Solution:

x and y = ?

GCD =16

first four quotients = 2

$\Rightarrow \frac{464}{192} \\\\\Rightarrow \frac{16 \times 29}{16 \times 12} \\\\\Rightarrow HCF = GCF =16$

$\Rightarrow \ HCF \times \ first \ quotients (2) + r_0\\\\\Rightarrow r_0 \times 2 +r_1\\\\\Rightarrow r_1 \times 2+ r_2\\\\\Rightarrow r_2 \times 2+ 0$

$16 \times 2 + 0\\32 \times 2 + 16\\80 \times 2 + 32\\192 \times 2 + 80$

The value of x and y is: $x = 464 \ \ \ y = 192$