Question

the gcd of (x+1) (x+2 ), (x+2) (x+3) and(x+1) (x+3) is

please only the answer​

Answer 1

Answer:

x2-1

Step-by-step explanation:

Let p(x)=x3+x2−x−1 and q(x)=x2−1

p(x)=x3+x2−x−1

         =x2(x+1)−1(x+1)

         =(x2−1)(x+1)

         =(x−1)(x+1)(x+1)

and

q(x)=x2−1

         =(x+1)(x−1)

∴ G.C.D of p(x) and q(x) =(x+1)(x−1)=x2−1