Question

The General Solution of ( dy)/dx =eˣ⁺ʸ is *

Answer 1

Step-by-step explanation:

We have,

$\frac{dy}{dx} = {e}^{x + y}$

$\implies \: \frac{dy}{dx} = {e}^{x}. {e}^{y}$

$\implies \: {e}^{ - y} dy = {e}^{x}dx$

Integrating both sides,

$\implies \int {e}^{ - y} dy = \int {e}^{x}dx$

$\implies - {e}^{ - y} = \ {e}^{x} + C$