The general solution of sin x-3 sin 2x + sin 3x = cos x - 3cos 2x + cos 3r i
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Step-by-step explanation:
sinx-3sin2x+sin3x=cosx-3cos2x+cos3x
sinx+sin3x-3sin2x=cosx+cos3x-3cos2x
2sin2xcosx- 3sin2x-2cos2xcosx+ 3cos2x=0
sin2x(2cosx-3)-cos2x(2cosx-3)=0
(2cosx-3)(sin2x-cos2x)=0
sin2x=cos2x as Cosx does not equal to3/2
2x=2nπ+- ( π/2)
x=nπ/2+π/8
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