Math, asked by sureshkumavat8, 4 months ago

The geometric mean of
three numbers 7,21 and 63 is
equal to​

Answers

Answered by sktripathix
2

Answer:

21

Step-by-step explanation:

geometric mean =√ 7 ×63

=√ 441

= 21

hope u understand

Answered by pulakmath007
1

The geometric mean of three numbers 7 , 21 and 63 is 21

Given :

Three numbers 7 , 21 and 63

To find :

The geometric mean of three numbers 7 , 21 and 63

Concept :

For three numbers a , b , c their geometric mean

\displaystyle \sf{  =  \sqrt[3]{abc}  }

Solution :

Step 1 of 2 :

Write down the given numbers

Here the given three numbers are 7 , 21 and 63

Step 2 of 2 :

Find the geometric mean

We know that for three numbers a , b , c their geometric mean

\displaystyle \sf{  =  \sqrt[3]{abc}  }

Thus for the three numbers are 7 , 21 and 63 geometric mean

\displaystyle \sf{  =  \sqrt[3]{7 \times 21 \times 63}  }

\displaystyle \sf{  =  \sqrt[3]{7 \times (3 \times 7) \times (3 \times 3 \times 7)}  }

\displaystyle \sf{ =  \sqrt[3]{3 \times 3 \times 3 \times 7 \times 7 \times 7}   }

\displaystyle \sf{ =  \sqrt[3]{ {3}^{3} \times  {7}^{3}  }   }

\displaystyle \sf{ = 3 \times 7  }

\displaystyle \sf{  = 21 }

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Learn more from Brainly :-

1. Find the smallest term of geometric progression 3,5,25/3 that exceeds 100.

https://brainly.in/question/26328002

3. 8 GM's are inserted between 3 and 4

then the product of 8 GM's

https://brainly.in/question/29050188

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