Question

The given diagram is a trapezium find the length of BC and the area of trapezium Assume AB = 5cm AD = 4cm CD = 8 cm.

Answer 1

hope it helps.....

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Answer 2

Thus, Length of $BC$ is $5cm$ and area of trapezium is $26cm^{2}$

Step-by-step explanation:

Given,

$ABCD$ is a trapezium where $AB=5cm$ , $AD=4cm$ and $CD=8cm$

From figure,

$AD=BE=4cm$ , $AB=DE=5cm$

∴$CE=CD-DE$

⇒$CE=(8-5)=3cm$

From,

$\triangle BCE$,

$BC =\sqrt{CE^{2}+BE^{2} }$

⇒$BC =\sqrt{3^{2}+4^{2} }$

∴$BC=5cm$

We know,

Area of trapezium$=\frac{AB+CD}{2}\times BE$

$=\frac{5+8}{2}\times 4$

$=13\times 2$

$=26$$cm^{2}$

∴ Length of $BC$ is $5cm$ and area of trapezium is $26cm^{2}$