Question

The given figure ABCD is parallelogram. AP is I to DB and CQ is I DB Prove that:
∆APD ∆CQB and AP = CQ.​

Answer 1

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Step-by-step explanation:

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Answer 2

Answer:

∆ABD and ∆BCD

/_APB=90°

/_CQD=90°

therefore /_APB=/_CQD. .......................(1)

AB=DC (common side).............(2)

AD=BC (common side)...............(3)

∆ABD≈∆BCD (by SSA construction)

therefore AP = CQ (C.P.C.T.)