the given figure, if AB || CD, and ∠HEB = 60°, ∠BEG = 40°, ∠GFD = 30°.Find ∠EGF, ∠AEF and ∠EFC.
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As per the diagram, lines CD∣∣EF and CE is transveral.
We know that sum of interior angles is equal to 180o
∠ECD+∠CEF=180°
∠ECD+130°=180°
∠ECD=180−130°
∠ECD=50°
As per the diagram, lines AB∣∣CD and CA is transveral.
We know that alternate angles are equal.
∠BAC=∠ACD
∠BAC=∠ACE+∠ECD
70°=∠ACE+50°
20°=∠ACE
∴∠ACE=20°
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