Question

The given figure shows a circle with centre O and diameter PR such that chord ST is parallel to PR. If ang RQT= 55°, then find angRTS.​

Answer 1

Answer:

Let the radius of a circle be x

So, OC=OD=x

As, OB=OE+EB

x=OE+4 [Since Ob is the radius and EB=4 cm given]

OE=x−4

We know that if a line drawn from the centre to the chord bisects the chord, then it is perpendicular to the chord

Hence, OE⊥CD

In △OED

OE

2

+ED

2

=OD

2

(x−4)

2

+8

2

=x

2

x

2

+16−8x+64=x

2

−8x+80=0

8x=80

x=10 cm

Thus, radius of the circle is 10 cm.

solution

Answer 2

Step-by-step explanation:

please check the answers