the given figure shows a rhombus in which OA = 3x + 7 ,OC = 5x-3 and OD = 10.Find the values of x and y
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THE GIVEN FIGURE IS A RHOMBUS WHICH HAS 4 SIDES.
SO, SUM OF INTERIOR ANGLE.
= (N-2)×180°
= (4-2)×180°
= 2×180°
= 360°
WE KNOW THAT,
OA = 3X + 7,
OC = 5X-3,
AND, OD = 10.
O is a point within a quadrilateral ABCD, show that OA + OB + OC + OD > AC + BD. ... In a || gm ABCD, if ∠A = (2x + 25)° and ∠B = (3x − 5)°, find the value of x and ... A rhombus has four equal sides.
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