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the given figure shows a rhombus in which OA = 3x + 7 ,OC = 5x-3 and OD = 10.Find the values of x and y​

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Answered by Xxadit17xX
1

Answer:

THE GIVEN FIGURE IS A RHOMBUS WHICH HAS 4 SIDES.

SO, SUM OF INTERIOR ANGLE.

= (N-2)×180°

= (4-2)×180°

= 2×180°

= 360°

WE KNOW THAT,

OA = 3X + 7,

OC = 5X-3,

AND, OD = 10.

O is a point within a quadrilateral ABCD, show that OA + OB + OC + OD > AC + BD. ... In a || gm ABCD, if ∠A = (2x + 25)° and ∠B = (3x − 5)°, find the value of x and ... A rhombus has four equal sides.

BETA JI, AAPNE PIC MEIN X AUR Y MENSION HI NAHI KIYA TO MEIN KISKKI VALUE NIKALU!!

Explanation:

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