the given figure triangle ABC in DF are similar if area of triangle ABC is equal to 49 centimetre square square and square of triangle d e f is equal to 64 CM square and ac is equal to 4.8 cm find DF
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Heya !!!
Area of triangle ABC = 49 cm²
And,
Area of triangle DEF = 64 cm²
AC = 4.8 cm
As we know that the area of two similar triangles is equal to the square of their corresponding sides.
Therefore,
Area of ∆ABC/ Area of ∆DEF = (AC/DF)²
49 / 64 = (4.8/DF)²
49 / 64 = 23.04 / DF²
DF² = 23.04 × 64 / 49
DF² = 1474.56/49
DF² = 30.09
DF = ✓30.09
DF = 5.48 cm
★ HOPE IT WILL HELP YOU ★
Area of triangle ABC = 49 cm²
And,
Area of triangle DEF = 64 cm²
AC = 4.8 cm
As we know that the area of two similar triangles is equal to the square of their corresponding sides.
Therefore,
Area of ∆ABC/ Area of ∆DEF = (AC/DF)²
49 / 64 = (4.8/DF)²
49 / 64 = 23.04 / DF²
DF² = 23.04 × 64 / 49
DF² = 1474.56/49
DF² = 30.09
DF = ✓30.09
DF = 5.48 cm
★ HOPE IT WILL HELP YOU ★
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