Question

The gram molar mass of the ca3(Po4)2is?​

Answer 1

Answer:

The GMM is 310 g.

Explanation:

amu of Ca = 40

amu of P = 31

amu of O = 16

So,

GMM = [40*3]+2[31+(16*4)]

= 120+2[31+64]

= 120+(2*95)

= 120+190

= 310 g

Hope this helps.

Answer 2

ATOMIC MASS of Ca=40 , P=31 , O=16

so Ca3(PO4)2

 => 40*3 + 31*2 + 16*4*2 gm or amu

 => 120 + 62 + 128 gm or amu

 => 120 + 190 gm or amu

 => 310 gm or amu ( ANS )