The graph given below is the distance-time graph of an object: [3] a. Find the speed of the object during first four seconds of its journey. b. How long was it stationary? c. Does it represent a real situation? Justify your answer.
Answers
Explanation:
The line OP, i.e. the first 4 seconds indicates uniform speed. Thus the speed of the object during this time interval will be the slope of line OP.
begin mathsize 12px style equals fraction numerator 75 minus 0 over denominator 4 minus 0 end fraction equals 18.75 space straight m divided by straight s end style
(ii) PQ is parallel to time axis, so speed is zero. Thus, the object is stationary between the time interval 14 s to 4 s.
Thus, the object is stationary for 14 - 4 = 10 s.
Answered by | 15th Jun, 2016, 12:20: PM
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