The graph of equation 5x-3y=20 intersects the x-axis at point ......................
Answers
Answer:
4
Step-by-step explanation:
put y=0
then we find 5x=20
so x=20/5=4
therefore the point is (4,0)
The graph of equation 5x - 3y = 20 intersects the x-axis at point (4,0)
Given :
The equation of the line 5x - 3y = 20
To find :
The point where graph of the line intersects the x-axis
Solution :
Step 1 of 2 :
Write down the given equation of the line
The given equation of the line is
5x - 3y = 20 - - - - - - (1)
Step 2 of 2 :
Find the point where graph of the line intersects the x-axis
Since the line intersects the x-axis
∴ y = 0
Putting y = 0 in Equation 1 we get
5x - ( 3 × 0 ) = 20
⇒ 5x - 0 = 20
⇒ 5x = 20
⇒ x = 20/5
⇒ x = 4
Hence the required point is (4,0)
The graph of equation 5x - 3y = 20 intersects the x-axis at point (4,0)
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