Question

The graph of linear equation X +3y = 2,cuts the y -axis at
a. (2,0)
b. (0,2
c. (0,1)
d. (1,1)

Answer 1

Answer:

(0,2) it is the right answer of question I hope it is useful to you please follow me also brilliant answer and please like also

Answer 2

$Given \: Linear \: equation \:in \:two \\variables \: x \: and \:y : \\ x + 3y = 2$

$Convert \: given \: equation \: into \\two \: intercepts \:form :$

$\boxed { \frac{x}{\blue{a}} + \frac{y}{\pink{y}} = 1 }$

$Where , \blue {a} = x - intercept \: and \\\pink{b} = y - intercept$

/* Dividing each term by 2, we get */

$\frac{x}{2} + \frac{3y}{2}= \frac{2}{2}$

$\implies \frac{x}{2} + \frac{y}{\frac{2}{3}}= 1$

Therefore.,

$Graph \: of \: linear \: equation \: x + 3y = 2 \\cuts \: x - axis \: at \: ( 2 , 0 ) \: and \: y - axis \:at \\( 0, \frac{2}{3} )$

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