Question

the graph of the equation 2x-y=4 and x+y= -1 intersect each other at point p(a,b)​

Answer 1

EXPLANATION.

Graph of the equation.

⇒ 2x - y = 4.

⇒ x + y = -1.

As we know that,

From equation (1), we get.

⇒ 2x - y = 4.

Put the value of x = 0 in equation, we get.

⇒ 2(0) - y = 4.

⇒ - y = 4.

⇒ y = -4.

Their Co-ordinates = (0,-4).

Put the value of y = 0 in equation, we get.

⇒ 2x - (0) = 4.

⇒ 2x = 4.

⇒ x = 2.

Their Co-ordinates = (2,0).

From equation (2), we get.

⇒ x + y = -1.

Put the value of x = 0 in equation, we get.

⇒ (0) + y = -1.

⇒ y = -1.

Their Co-ordinates = (0,-1).

Put the value of y = 0 in equation, we get.

⇒ x + (0) = -1.

⇒ x = -1.

Their Co-ordinates = (-1,0).

Both curves intersect at a point = (1,-2).

Answer 2

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$\boxed{\text{Equation (1)}\: \longrightarrow}$ 2x - y = 4

•°• The equation becomes =

ㅤㅤㅤ➪ 2x = 4 + y

ㅤㅤㅤ➪ xㅤ= $\sf{\dfrac{4 + y}{2}}$

Let ,

ㅤㅤㅤ➪ y = 2

•°• ㅤx = $\sf{\dfrac{4 + 2}{2}}$

ㅤ➪ x = $\sf{\dfrac{6}{2}}$

ㅤ➪ x = 3

Let ,

ㅤㅤㅤ➪ y = 0

•°• x = $\sf{\dfrac{4 + 0}{2}}$

➪ x = $\sf{\dfrac{4}{2}}$

➪ x = $\sf{2}$

•°• Co-ordinate of Equation 1 is (3,2) & (2,0)

$\boxed{\text{Equation (2)}\: \longrightarrow}$ x + y = - 1

•°• The equation becomes =

ㅤㅤㅤ➪ x = - 1 - y

Let ,

ㅤㅤㅤ➪ y = 1

•°•ㅤ x = - 1 - y

ㅤ➪ x = - 1 - 1

ㅤ➪ x = - 2

Let ,

ㅤㅤㅤ➪ y = 2

•°•ㅤ x = - 1 - y

ㅤ➪ x = - 1 - 2

ㅤ➪ x = - 3

•°• Co-ordinate of Equation 2 is (-2,1) & (-3,2)

The Graph is attached in attachment*

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