Math, asked by labalamamatha48, 1 day ago

The graph of the linear equation 4 x - 5 y = 2 0 cuts y - axis at the point _________ .​

Answers

Answered by llMagicLilyll
3

Answer:

The given linear equation is 2x - y = 4

2x - y = 4

Put y = 0

2x -0 =4

⇒ 2x=4

.. X = 2

Substutute x = 2 in equation,

⇒ 2(2) - y = 4

⇒ 4-y=4

.. y = 0

⇒ (x, y) = (2,0)

→ The graph of the linear equation

2x-y = 4 cuts x-axis at (2,0).

Answered by rayyanuddin027
0

Answer:

Step-by-step explanation:

Since, the graph of linear equation 2x+3y=6 cuts the Y-axis.

So, we put x=0 in the given equation 2x+3y=6, we get

2×0+3y=6

⇒ 3y=6

⇒ y=63

∴ y=2

Hence, at the point (0,2), the given linear equation cuts the Y-axis.

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