The graph of the linear equation 4 x - 5 y = 2 0 cuts y - axis at the point _________ .
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Answered by
3
Answer:
The given linear equation is 2x - y = 4
2x - y = 4
Put y = 0
2x -0 =4
⇒ 2x=4
.. X = 2
Substutute x = 2 in equation,
⇒ 2(2) - y = 4
⇒ 4-y=4
.. y = 0
⇒ (x, y) = (2,0)
→ The graph of the linear equation
2x-y = 4 cuts x-axis at (2,0).
Answered by
0
Answer:
Step-by-step explanation:
Since, the graph of linear equation 2x+3y=6 cuts the Y-axis.
So, we put x=0 in the given equation 2x+3y=6, we get
2×0+3y=6
⇒ 3y=6
⇒ y=63
∴ y=2
Hence, at the point (0,2), the given linear equation cuts the Y-axis.
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