Math, asked by stardusta, 4 months ago

The graph of the linear equation y = -x passes through the point _____.​

Answers

Answered by sujanahmed93
3

Answer:

(0,0)

Since y = mx goes through origin.

Step-by-step explanation:

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Answered by arjamesbola07
1

Answer:Answer:

The easier way to solve this is to find the two points in the coordinate axis, and just draw a line that passes through the two points.

But let's be more complete:

Let's find the equations for each line:

A linear relationship can be written as:

y = a*x + b

where a is the slope and b is the y-axis intercept.

For a line that passes through the points (x1, y1) and (x2, y2), the slope can be written as:

a = (y2 - y1)/(x2 - x1).

1) Here the points are (2,2) and (4,5)

then the slope is:

a = (5 - 2)/(4 - 2) = 3/2

y = (3/2)*x + b

And to find the value of b, we just replace the values of one of the points in the equation, in this case i will use (2, 2)

2 = (3/2)*2 + b

2 = 3 + b

2 - 3 = b

-1 = b

y = (3/2)*x - 1

2) Here the points are (0,1/2) and (2,3/2)

then the slope is:

a = (3/2 - 1/2)/(2 - 0) = 1/2

y = (1/2)*x + b

And to find the value of b, we just replace the values of one of the points in the equation, in this case i will use (0, 1/2)

1/2 = (1/2)*0 + b

1/2 = b

y = (1/2)*x + 1/2

3) Here the points are (-1,2) and (5,0)

then the slope is:

a = (0 - 2)/(5 + 1) = -1/3

y = (-1/3)*x + b

And to find the value of b, we just replace the values of one of the points in the equation, in this case i will use (-1, 2)

2 = (-1/3)*-1 + b

2 = 1/3 + b

2 - 1/3 = b

5/3 = b

y = (-1/3)*x + 5/3

4) Here the points are (-5,-3) and (-3,5)

then the slope is:

a = (5 + 3)/(-3 + 5) = -4

y = -4*x + b

And to find the value of b, we just replace the values of one of the points in the equation, in this case i will use (-3, 5)

5 = -4*-3 + b

5 = 12 + b

5 - 12 = b

-7 = b

y = -4*x - 7

Step-by-step explanation:brainliest plssssss

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