The graph of y=2x^(2)+x-3 cuts x-axis at (1,0) and (-3/2,0). Find the zeroes of the polynomials.
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Graphically, the point where the curve cuts the X-Axis, the abscissa of that co-ordinate will be the zeroes of that polynomial.
Here co-ordinates are (1,0) and (-3/2,0)
so, zeroes of polynomial will be 1 and -3/2
Here co-ordinates are (1,0) and (-3/2,0)
so, zeroes of polynomial will be 1 and -3/2
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