Question

The graph of y = p(x) intersects x-axis at x = 2 and x= -3, then find the polynomial p(x)

Answer 1

Step-by-step explanation:

let alpha= 2 and beta = -3 are zeroes of p(x)

sum of zeroes = 2 + (-3)

= -1

product of zeroes = 2× -3

= -6

p(x) = x^2-(sum of zeroes)x+(product of zeroes)

= x^2 - (-1) x + ( -6)

= x^2 + x - 6

hence, x^2 + x - 6 is required polynomial

HOPE IT WILL HELP YOU ...........:D