The graph shows velocity of a moving bus during different time intervals. Calculate a) total distance covered by bus from 0 to N and time interval between p to Q being 20 sec b) the uniform acceleration and retardation of the bus
Answers
The graph shows the velocity of a moving bus during different time intervals.
To find : a) Total distance covered by bus from 0 to N
(b) The uniform acceleration and retardation of the bus.
solution : total distance covered by bus from 0 to N = area enclosed by the velocity time graph
= 1/2 × (PQ + ON) × LP
= 1/2 × (20s + 42s) × 100 m/s
= 3100 m
from O to P, bus is accelerating PQ bus is moving with constant speed and QN, bus is retarding.
uniform acceleration :
initial velocity, u = 0
final velocity, v = 100 m/s
time taken, t = 10s
using formula, v = u + at
⇒100 = 0 + a × 10
⇒a = 10 m/s²
uniform retardation :
initial velocity, u = 100 m/s
final velocity, v = 0
time taken, t = 12s
using formula, v = u + at
⇒0 = 100 + a × 12
⇒a = -100/12 = -8.33 m/s²
The graph shows the velocity of a moving bus during different time intervals.
To find : a) Total distance covered by bus from 0 to N
(b) The uniform acceleration and retardation of the bus.
solution : total distance covered by bus from 0 to N = area enclosed by the velocity time graph
= 1/2 × (PQ + ON) × LP
= 1/2 × (20s + 42s) × 100 m/s
= 3100 m
from O to P, bus is accelerating PQ bus is moving with constant speed and QN, bus is retarding.
uniform acceleration :
initial velocity, u = 0
final velocity, v = 100 m/s
time taken, t = 10s
using formula, v = u + at
⇒100 = 0 + a × 10
⇒a = 10 m/s²
uniform retardation :
initial velocity, u = 100 m/s
final velocity, v = 0
time taken, t = 12s
using formula, v = u + at
⇒0 = 100 + a × 12
⇒a = -100/12 = -8.33 m/s²