Physics, asked by moloychatterjeeschat, 11 months ago

The graph shows velocity of a moving bus during different time intervals. Calculate a) total distance covered by bus from 0 to N and time interval between p to Q being 20 sec b) the uniform acceleration and retardation of the bus

Answers

Answered by abhi178
17

The graph shows the velocity of a moving bus during different time intervals.

To find : a) Total distance covered by bus from 0 to N

(b) The uniform acceleration and retardation of the bus.

solution : total distance covered by bus from 0 to N = area enclosed by the velocity time graph

= 1/2 × (PQ + ON) × LP

= 1/2 × (20s + 42s) × 100 m/s

= 3100 m

from O to P, bus is accelerating PQ bus is moving with constant speed and QN, bus is retarding.

uniform acceleration :

initial velocity, u = 0

final velocity, v = 100 m/s

time taken, t = 10s

using formula, v = u + at

⇒100 = 0 + a × 10

⇒a = 10 m/s²

uniform retardation :

initial velocity, u = 100 m/s

final velocity, v = 0

time taken, t = 12s

using formula, v = u + at

⇒0 = 100 + a × 12

⇒a = -100/12 = -8.33 m/s²

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Answered by taneshqghube
0

The graph shows the velocity of a moving bus during different time intervals.

To find : a) Total distance covered by bus from 0 to N

(b) The uniform acceleration and retardation of the bus.

solution : total distance covered by bus from 0 to N = area enclosed by the velocity time graph

= 1/2 × (PQ + ON) × LP

= 1/2 × (20s + 42s) × 100 m/s

= 3100 m

from O to P, bus is accelerating PQ bus is moving with constant speed and QN, bus is retarding.

uniform acceleration :

initial velocity, u = 0

final velocity, v = 100 m/s

time taken, t = 10s

using formula, v = u + at

⇒100 = 0 + a × 10

⇒a = 10 m/s²

uniform retardation :

initial velocity, u = 100 m/s

final velocity, v = 0

time taken, t = 12s

using formula, v = u + at

⇒0 = 100 + a × 12

⇒a = -100/12 = -8.33 m/s²

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