Question

the graph to express the inequality y<=1/2x is indicated by​

Answer 1

Here you are friend First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.

For:

x

=

0

y

=

(

1

2

⋅

0

)

−

1

y

=

0

−

1

y

=

−

1

or

(

0

,

−

1

)

For:

x

=

2

y

=

(

1

2

⋅

2

)

−

1

y

=

1

−

1

y

=

0

or

(

2

,

0

)

We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.

graph{(x^2+(y+1)^2-0.025)((x-2)^2+y^2-0.025)(y-(1/2)x+1)=0 [-10, 10, -5, 5]}

Now, we can shade the right side of the line. And for the inequality we need to make the boundary line a dashed line because the inequality operator does not contains an "or equal to" clause.

graph{(y-(1/2)x+1) < 0 [-10, 10, -5, 5]}