Physics, asked by tajammul81, 1 month ago

The gravitational attractive force between two masses is F. if the masses of both the objects are doubled. what will be the gravitational attractive force? the opstion is a)four time b)halved c)doubled d)one fourth ​

Answers

Answered by Steph0303
89

Answer:

The formula to find the Gravitational force present between 2 masses is given as:

\boxed{ \bf{F_G = \dfrac{G.m_1.m_2}{d^2}}}

Where, G refers to the universal gravitation constant, m₁ and m₂ are the masses and d refers to the distance between the masses.

Now it is said that the masses are doubled. Hence the new Gravitational Force is given as:

\implies F'_G = \dfrac{G.(2m_1).(2m_2)}{d^2}\\\\\\\implies F'_G = \dfrac{4G.(m_1).(m_2)}{d^2}\\\\\\\implies \boxed{ \bf{F'_G = 4 \times F_G}}

Hence the new gravitational force is four times the original force.

Hence Option (A) is the correct answer.

Answered by Anonymous
205

Answer:

Question :-

  • The gravitational attractive force between two masses is F. If the masses of both the objects are doubled what will be the gravitational attractive force.

  1. Four times.
  2. Halved.
  3. Doubled.
  4. One fourth.

Answer :-

  • Here the gravitational attractive force between is Four times as that of original force

Given :-

  • The gravitational attractive force between two masses is F. And also given that masses are doubled as per to original force.

To find :-

  • What will be the gravitational attractive force between two masses.

Solution :-

  • Here one thing we want know the formulae of gravitational attractive force
  • That is ,

FG =  \frac{G.m1.m2}{ {d}^{2} }

  • Here,

  1. G denotes universal gravitational constant.
  2. m1 and m2 denotes gravitational attractive force between two masses.
  3. d denotes distance travelled between two masses.

♧According to the given question, the gravitational attractive force formulae becomes,

  • F'G= G(2m1)×(2m2)/d^2.

  • In the question given that ,
  • Gravitational attractive force between two masses is doubled.
  • So,

  • F' G= 4G.(m1).(m2)/d^2.

  • And this becomes as,

  • F'G= 4× FG.

\mathcal\red{Therefore ,}

  • The gravitational attractive force between two masses is four times as that of original force.

\mathcal\red{Hence,}

  • Option A is the correct answer for your question.

\mathcal\purple{Used formulae,}

  • Here we used
  • Gravitational attractive force between two masses formulae here we used to get the perfect answer.

♧Hope it helps u mate.

\mathcal\purple{Thank you .}

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