Question

The gravitational force between 2 objects is F. How will the force change when the distance between them is reduced to 1/4th?

Answer 1

HeYa..!!!
here is Ur answer.....

We know, that the force of gravitation between two objects is inversely proportional to the square of distance between them.
That is, F∞1/r²
Now when the distance between two objects is reduced to 1/4tg that's is made ¼,then the force between them will become 16
i.e. (1/¼)²
= 16

Answer 2

Answer:

F = (G m1m2)/r2

Where m1m2 = the masses of the two bodies,

r = distance between them

G = gravitational Constant

When the distance is reduced to half i.e. r’ = (1/2) r then,

F’ = (G m1m2)/r2

= (G m1m2)/(r/2)2

= (4 G m1m2)/ (r2) = 4F

Therefore when the distance between the objects is reduced to half, then the force of gravitation increases by four times the original force.

Explanation:

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